Exercise 1.  Calculating Total Manure Produced,
Nutrient Content and Value of Manure

(adapted from Olson and McKenzie, 1998)

 

Exercise 1a. Determine total manure produced.


Livestock
Type
A
Animal numbers
B
Manure Produced*
(tons/head/year)
C
Number of months
in confinement
/ 12
D
= A x B x C
Total Manure Produced
for Land Application
(tons/year)



/ 12



/12



/ 12



/ 12
* Refer to Data Sheet #1 and #2 Total

Data Sheet #1 - Solid manure production (AAFRD 1995a).

Livestock type tons/year
Beef Open lot 2.4
Beef Paved 3.6
Dairy Tie stall 27.3
Poultry per 100 layers 2.1
Poultry per 100 broilers 1.2
Poultry per 100 breeders 2.9
Poultry per 100 turkey hens 5.8
Poultry per 100 turkey toms 6.6
Poultry per 100 turkey broilers 4.7
Sheep Ewes 0.6
Sheep Lambs 0.1
Bison   1.3
Elk   1.1
Horse   8.4

 

Data Sheet #2 - Liquid Manure Production (AAFRD 1995a).

Livestock Type gallons/year tons/year
Sows Farrow - finish 5272 26.4
Sows Farrow – wean 1622 8.1
Hogs Feeders 568 2.8
Dairy Free stall 7300 36.5
Dairy Tie stall 6489 32.4
Beef Closed 1460 7.3
Poultry 100 layers 1810 9.1

 

Exercise 1b. Calculating the Nutrient Content of Manure.

Livestock A*
Total manure
produced for
land application
(tons)
B**
Manure
Crop N
content (lbs/ton)
C
=A x B

Total Crop N available
(lbs)
D**
Manure Crop P2O5 content (lbs/ton)
E
=A x D

Total P2O5
available (lbs)
F**
Manure Crop K2O content (lbs/ton)
G
= A x F

Total K2O
available (lbs)
Beef






Dairy






Hogs






Poultry






Other







Other







Other







Other







Total
Total
Total
* Column D from Ex.1a
** Refer to Data Sheet 3

 

Data sheet #3. - Manure nutrient content for various livestock types (AAFRD 1995a).

Manure nutrient content for various livestock types. *, **
Livestock type Moisture
(%)
Total N
(lbs/ton)
Available N
(lbs/ton)
Crop N
(lbs/ton)
P2O5
(lbs/ton)
K2O
(lbs/ton)
Beef Open lot 50 17 4.4 5.1 11 16
Beef Paved 65 13 5.0 4.4 4.0 9.0
Beef Closed 92 9.0 3.9 3.3 4.0 10
Dairy Free stall 92 9.0 4.1 3.7 4.0 10
Dairy Tie stall 80 11 4.6 4.2 4.0 10
Hogs Farrow-finish 96 7.0 3.2 3.0 5.0 4.0
Hogs Farrow-wean 96 7.0 3.2 3.0 5.0 4.0
Hogs Feeder 96 7.0 3.2 3.0 5.0 4.0
Chicken Layers (solid) 60 32 25 22 56 20
Chicken Layers (liquid) 90 19 15 13 34 12
Chicken Broilers 35 37 25 21 30 20
Chicken Breeders 35 39 26 23 60 20
Turkey Hens 35 37 25 21 30 20
Turkey Toms 35 37 25 21 30 20
Turkey Broilers 35 37 25 21 30 20
Sheep Ewe & Lamb 50 14 5.6 5.3 9.0 25
Bison   n/a 13 3.9 4.5 10 12
Elk   n/a 13 3.9 4.5 10 12
Horse   n/a 12 6.0 5.7 6.0 12
* Adopted from Appendix A-1 in the Code of Practice for the Safe and Economic Handling of Animal Manures. 1995. Alberta Agriculture, Food and Rural Development. AGDEX 400/27-2
** Based on averages from a variety of sources. Actual farm values may vary greatly.
n/a    values not available
Total N: Includes both inorganic (nitrate and ammonium nitrogen) and organic nitrogen. The organic portion is not available to the plant without further microbial mineralization into available (inorganic) nitrogen.
Available N: This is the portion of the total nitrogen that is in the inorganic (nitrate and ammonium), plant available form at the time of manure sampling. Also known as inorganic or mineral N.
Crop N: This is an estimate of the available nitrogen plus the portion of the organic nitrogen that is mineralized over the growing season minus the volatilization losses over the growing season.
P2O5: Phosphorus is expressed as phosphate equivalent of manure because phosphorus exists in both inorganic and organic forms.
K2O: Potassium is expressed as lbs of potash/ton of manure.

 

Exercise 1c. Nutrient value of manure

What is the economic value of manure? Manure may appear to be a cost to the producers in terms of removal, storage and disposal. But manure has a nutrient value and this can be expressed as a commercial fertilizer equivalent.
Nutrient Weight of
nutrient in manure(lbs)
****Commercial
fertilizer cost
($/lb)
Total value
of manure nutrient
($)
Beef
N*   x $ 0.27 =  
P2O5**   x $ 0.33 =  
K2O***   x $ 0.16 =  
Dairy
N*   x $ 0.27 =  
P2O5**   x $ 0.33 =  
K2O***   x $ 0.16 =  
Hogs
N*   x $ 0.27 =  
P2O5**   x $ 0.33 =  
K2O***   x $ 0.16 =  
Poultry
N*   x $ 0.27 =  
P2O5**   x $ 0.33 =  
K2O***   x $ 0.16 =  
Other
N*   x $ 0.27 =  
P2O5**   x $ 0.33 =  
K2O***   x $ 0.16 =  
Other
N*   x $ 0.27 =  
P2O5**   x $ 0.33 =  
K2O***   x $ 0.16 =  
Other
N*   x $ 0.27 =  
P2O5**   x $ 0.33 =  
K2O***   x $ 0.16 =  
Care should be taken not to confuse these calculated economic values with market values. If a particular nutrient is not required then it would have no value. This exercise is a simple means to compare manure to commercial fertilizer. Manure also adds benefits to the soil such as improved soil structure, water-holding capacity, and reclamation of eroded land. It is difficult to determine economic values for these benefits.
* Column C from exercise 1b
** Column E from exercise 1b
*** Column G from exercise 1b
**** Cost of commercial fertilizer in central Alberta – March 1, 2000.